Script: To find the size of the tables in a database

SELECT
table_name = SCHEMA_NAME(o.[schema_id]) + '.' + o.name

, data_size_mb = CAST(do.pages * 8. / 1024 AS DECIMAL(8,4))

FROM sys.objects o

JOIN (




SELECT
p.[object_id]

, total_rows = SUM(p.[rows])

, total_pages = SUM(a.total_pages)

, usedpages = SUM(a.used_pages)

, pages = SUM(




CASE
WHEN it.internal_type IN (202, 204, 207, 211, 212, 213, 214, 215, 216, 221, 222) THEN 0

WHEN a.[type]! = 1 AND p.index_id < 2 THEN a.used_pages

WHEN p.index_id < 2 THEN a.data_pages ELSE 0




END
)
FROM sys.partitions p

JOIN sys.allocation_units a ON p.[partition_id] = a.container_id

LEFT JOIN sys.internal_tables it ON p.[object_id] = it.[object_id]

GROUP BY p.[object_id]

) do ON o.[object_id] = do.[object_id]

WHERE o.[type] = 'U'

CPU consumption

--from SQLAuthority website
--SQL SERVER – Who is consuming CPU on my SQL Server?

WITH DB_CPU_Statistics




AS


(SELECT pa.DatabaseID, DB_NAME(pa.DatabaseID) AS [Database Name], SUM(qs.total_worker_time/1000) AS [CPU_Time_Ms]

FROM sys.dm_exec_query_stats AS qs WITH (NOLOCK)

CROSS APPLY (SELECT CONVERT(INT, value) AS [DatabaseID]

FROM sys.dm_exec_plan_attributes(qs.plan_handle)

WHERE attribute = N'dbid') AS pa

GROUP BY DatabaseID)

SELECT ROW_NUMBER() OVER(ORDER BY [CPU_Time_Ms] DESC) AS [CPU Ranking],

[Database Name], [CPU_Time_Ms] AS [CPU Time (ms)],

CAST([CPU_Time_Ms] * 1.0 / SUM([CPU_Time_Ms]) OVER() * 100.0 AS DECIMAL(5, 2)) AS [CPU Percent]

FROM DB_CPU_Statistics

WHERE DatabaseID <> 32767 -- ResourceDB

ORDER BY [CPU Ranking] OPTION (RECOMPILE);