Find age based on date - TSQL

--this query finds the current ( as of the date the query is run) age of the person.

declare @dob datetime

set @dob = '07/12/1966'

select CASE

WHEN dateadd(year, datediff (year, @dob, GETDATE()),@dob) > GETDATE()

THEN datediff (year, @dob, GETDATE()) - 1

ELSE datediff (year, @dob, GETDATE())

END as Age

--select dateadd(year, datediff (year, @dob, GETDATE()),@dob)

--select datediff (year, @dob, GETDATE())